Sunday, January 19, 2014

Method to solve problems related to Bar-Charts.

Posted by Jasleen Behl

Today I'm going to discuss a problem related to bar charts in Data interpretation. In almost every bank exam, one set is always asked from this section in Quantitative aptitude. I'm going discuss the problem with a same pattern which has already been asked in so many exams.

Steps to solve problems of Data Interpretation: Bar-Charts

  • Study the chart first and have an idea about the values presented in the form of bar-charts.
  • To make the problem simple get an idea about the range of values presented in bar-chart.
  • If you want to save your time, read the question and just concentrate on bar-chart itself and do the calculations on it.
Problem1: Study the following graph and answer the questions:


X-axis is represented as different restaurants i.e. P, Q, R, S and T and Y- axis is represented as consumption of rice, wheat and sugar in kilograms.

1. Find the ratio of amount of rice, wheat and sugar consumed by restaurant Q to the amount consumed by restaurant T.

2. Find the average amount of rice, wheat and sugar consumed by all restaurants.

3. Rice consumed by restaurant R is what percent of rice consumed by all restaurants?

4. What is the difference between the average amount of wheat and average amount of sugar consumed by all restaurants together?

Solution: First of all, study the chart and analyze it. You will come to know the following points:

  • X-Axis `to` Restaurants (P, Q, R, Sand T)
  • Y-Axis `to` Amounts in kilograms (Lies between 400-900)
  • Three bars `to` Rice, Wheat and Sugar
 Now, lets start solving the questions:

1. Amount of rice, wheat and sugar consumed by restaurant Q  = `600+ 900+ 550`
⇒`2050`
  Amount consumed by restaurant T = `700+ 800+ 500`
⇒ `2000`

Now, Ratio of both of above value i.e. Q: T          
⇒ `2050` = `2000`
⇒ `41`: `40`

2. To find average amount of rice, wheat and sugar consumed by all restaurants.
Amount of rice, wheat and sugar consumed by restaurant:

P = `800+ 500+ 500`= `1800`
Q = `600+ 900+ 550`= `2050`
R = `500+ 600+ 400`= `1500`
S = `800+ 700+ 600`= `2100`
T = `700+ 800+ 500`= `2000`

Average = `(1800+ 2050+ 1500+ 2100+ 2000)/5`

⇒`(9450)/5`
⇒`1890`

3. Let Rice consumed by restaurant R = `x`% of rice consumed by all restaurants together
Let  Rice consumed by restaurant R = A i.e. `500`
rice consumed by all restaurants together= B i.e. `800+ 600+ 500+ 800+ 700` = `3400`

So, A = `x`% of B

⇒ `x`= `A/B times 100`

⇒ `x`= `(500)/(3400) times 100`

⇒`x` = `14.7`%

4. Difference between the average amount of wheat and average amount of sugar consumed by all restaurants together.

 Average amount of wheat by all restaurants = A =`(500+ 900+ 600+ 700+ 800)/5`

⇒`3500/5`

⇒ `700`

Average amount of sugar by all restaurants = B =`(500+ 550+ 400+ 600+ 500)/5`

⇒`2550/5`

⇒`510`

Difference = `A-B` = `700- 510`

 ⇒ `190`kg

You are free to ask anything. I will try to update more problems soon.
Problem related to Data interpretation: Tables.

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