The ratio is defined as the quantitative relation between two values showing the number of times one value contains or is contained within the other.

The ratio in the mathematical term used to compare two similar quantities expressed in the same units.

The ratio of two numbers ‘x’ and ‘y’ is denoted as x:y

####

If `\frac { a }{ b } = \frac { c }{ d } then \frac { (a+b) }{ b } = \frac { (c+d) }{ d }`

###
Trick 1:

We cannot use x for solving

Total parts = 4 + 5 = 9

First number = `(\frac { 4 }{ 9 })`900 = 400

Second number = `(\frac { 5 }{ 9 })`900 = 500

Total parts = 5 + 7 + 3 = 15

First number = `(\frac { 5 }{ 15 })`1500 = 500

Second number = `(\frac { 7 }{ 15 })`1500 = 700

Third number = `(\frac { 3 }{ 15 })`1500 = 300

As two parameters which are weight and cost are directly proportional.

Hence, `\frac { W1 }{ W2 } = \frac { C1 }{ C2 } `

`\frac { 3 }{ 8 } = \frac { 45000 }{ C2 } `3/8 = 45000/C2

C2 = 120000

If parameter A and B are inversely proportional then they will satisfy the following equation

`\frac { A1 }{ A2 } = \frac { B1 }{ B2 } `

\begin{matrix} A: & B: & C \\ x & y & y \\ m & m & n \end{matrix}

A: B: C → x` \times ` m : y ` \times ` m : y ` \times ` n

\begin{matrix} A: & B: & C \\ 4 & 5 & 5 \\ 3 & 3 & 4 \end{matrix}

A:B:C → 4` \times `3 : 5` \times `3 : 5` \times `4

A:B:C → 12:15:20

If the ratio of a salary of A and B is 2:3, B and C is 4:5, C and D is 6:7. If the salary of A is 48000 then Find the salary of D.

\begin{matrix} A: & B: & C: & D \\ 2 & 3 & 3 & 3 \\ 4 & 4 & 5 & 5 \\ 6 & 6 & 6 & 7\end{matrix}

A:B:C:D à 48: 72: 90: 105

A:D = 48:105

`\frac { A }{ D }` = `\frac { 48 }{ 105 }`

`\frac { 48000 }{ D }` = `\frac { 48 }{ 105 }`

D’s salary = 105000

Ratio ⟶ 3: 5

Assume the actual number 3x and 5x

According to the question,

`(3x)^{ 2 }` + `(5x)^{ 2 }` = 30600

`34x^{ 2 }` = 30600

`x^{ 2 }` = 900

x = 30

Substitute the value of x in 3x and 5x to find numbers

Hence the numbers are 90 and 150

Value Ratio⟶ V1 : V2 : V3

(Q1` \times `V1) + (Q2` \times `V2) + (Q3` \times `V3) = T

Common factor X = Total Amount/ T

Quantity of each coin = Q1X , Q2X, Q3X

T = (5` \times `2) + (10` \times `4) + (20` \times `5)

T = 150 paisa = Rs. 1.50

X = `\frac { 4.50 }{ 1.50 }`4.50/ 1.50 = 3

Hence the quantity of 20 paisa coins = 5 ` \times ` 3 = 15 coins

Value Ratio ⟶ 6:7:9

Coins Ratio ⟶ 6` \times `1: 7` \times `2: 9` \times `4

3:7:18

Number of 50 paisa coins = `(\frac { 7 }{ 28 }) \times ` 440 = 110

\begin{matrix} A: & B: & C \\ 2 & 5 & 5 \\ 7 & 7 & 3 \end{matrix}

A:B:C = 7`\times `2 : 7`\times `5 : 5`\times `3

A:B:C = 14:21:15

Solution:

Let us consider the length of bigger part be 1 m and the smaller part be ‘x’ m.

So length of full stick = (1+x) m

Acc. to the ques.

`\frac { 1 }{ x } ` = `\frac { 1 + x }{ x } `

`x^{ 2 }` + x = 1

x = `\frac { (-1+\sqrt { 5 } ) }{ 2 }` (As the length will be positive)

Let us suppose the salary of A be Rs. x, B be Rs. y and C be Rs. Z

Then the savings of them is

`\frac { (x\times 25)}{100}`, `\frac { (y\times 15)}{100}`, `\frac { (Z\times 20)}{100}`

`\frac { x }{ 4 }` , `\frac { 3y }{ 20 }`, `\frac { z }{ 5 }` = 8:9:20

x:y:z = 32:60:100 = 8:15:25

B’s salary will be `(\frac { 15 }{ 48 })\times ` 96000 = Rs. 30000

Initial ratio of seats = 5:7:8

There is increase of 40%, 50% and 75%

New ratio of seats:

5`\times ` 140% : 7`\times `150% : 8`\times ` 175%

7:`\frac { 21 }{ 2 } `:14

2:3:4

Hence the new ratio of seats is 2:3:4

Given è Ratio of fares = 4:1

Ratio of number of passengers = 2:17

Ratio of amount collection = 4`\times `2 : 1`\times `17 = 8:17

Hence amount collected from second-class passengers is

`(\frac {17 }{ 25 } )\times ` 2500 = 1700

Required amount collection is Rs. 1700

Let us consider the total weight be ‘x’

Acc. to ques. Weight is proportional to square of weight

`x^{ 2 }` = 1296

X = 36

After breakage ratio of weight = 1:2:3

Actual Weight = 6, 12, 18

Total value = `6^{ 2 }` + `12^{ 2 }` + `18^{ 2 }`

= 36+144+324 = 504

Loss after breakage = 1296 – 504 = 792

For two ratio to be equal there is requirement of four variables.

If `\frac { a }{ b } = \frac {c }{ d } ` then a, b, c, d are said to be in proportion

This is expressed as ‘a’ is to ‘b’ is to ‘c’ is to ‘d’

And written as a:b :: c:d

( product of means = product of extremes)

a:b = b:c

Middle number b is called mean proportion and a and c are called extreme numbers.

`B^{ 2 }` = A`\times `C
Given it is third proportion where a = 6 and b = 12

`B^{ 2 }` = A`\times `C

`12^{ 2 }` = 6 `\times ` C

C = 24

The ratio in the mathematical term used to compare two similar quantities expressed in the same units.

The ratio of two numbers ‘x’ and ‘y’ is denoted as x:y

**Note:****Fractions and ratio are same but the only difference is that ratio is unit less quantity but fraction is not.**### Basics Properties of Ratio

- A:B = mA : mB where m is constant
- a:b:c = A:B:C is equivalent to `\frac { a }{ A } = \frac { b }{ B } = \frac { c }{ C } `
- This property has to be used in the ratio of three things
- The inverse ratios of two equal ratios are equal. This property is called invertendo.
- If `\frac { a }{ b } = \frac { c }{ d } then \frac { b }{ a } = \frac { d }{ c } `
- The ratio of antecedents and consequents of two equal ratio are equal. This property is called Alternendo.
- If `\frac { a }{ b } = \frac { c }{ d } then \frac { a }{ c } = \frac { b }{ d } `

####
**Componendo:**

If `\frac { a }{ b } = \frac { c }{ d } then \frac { (a+b) }{ b } = \frac { (c+d) }{ d }`#### Dividendo:

If `\frac { a }{ b } = \frac { c }{ d } then \frac { (a-b) }{ b } = \frac { (c-d) }{ d }`#### Componendo-Dividendo:

If `\frac { a }{ b } = \frac { c }{ d } then \frac { (a+b) }{ (a-b) } = \frac { (c+d) }{ (c-d) }`## RATIO TRICKS

###
Trick 1: **Splitting number in the given ratio**

**1. Divide 900 in the ratio 4:5**We cannot use x for solving

Total parts = 4 + 5 = 9

First number = `(\frac { 4 }{ 9 })`900 = 400

Second number = `(\frac { 5 }{ 9 })`900 = 500

**2. Divide 1500 in the ratio 5:7:3**Total parts = 5 + 7 + 3 = 15

First number = `(\frac { 5 }{ 15 })`1500 = 500

Second number = `(\frac { 7 }{ 15 })`1500 = 700

Third number = `(\frac { 3 }{ 15 })`1500 = 300

### TRICK 2: Directly Proportional

When two parameters are directly proportional if one parameter increases the other one also increases and if one decreases another one also decreases.

If parameters A and B are directly proportional then they will satisfy the following equation

`\frac { A1 }{ A2 } = \frac { B1 }{ B2 } `If parameters A and B are directly proportional then they will satisfy the following equation

#### Example:

**Price of diamond is directly proportional to its weight. If 3 grams of diamond costs Rs 45000. Then what will be the price of 8 grams of the diamond.****Solution:**As two parameters which are weight and cost are directly proportional.

Hence, `\frac { W1 }{ W2 } = \frac { C1 }{ C2 } `

`\frac { 3 }{ 8 } = \frac { 45000 }{ C2 } `3/8 = 45000/C2

C2 = 120000

### TRICK 3: Inverse Proportional

When two parameters are inversely proportional if one parameter increases then other one decreases and if the one decreases then the other increases.If parameter A and B are inversely proportional then they will satisfy the following equation

`\frac { A1 }{ A2 } = \frac { B1 }{ B2 } `

### TRICK 4:

If the ratio’s A:B and B:C are given then we can find A:C without solving any equation\begin{matrix} A: & B: & C \\ x & y & y \\ m & m & n \end{matrix}

A: B: C → x` \times ` m : y ` \times ` m : y ` \times ` n

#### Examples:

**If the ratio of A:B is 4:5 and the ratio of B:C is 3:4. Then find the ratio A:C**\begin{matrix} A: & B: & C \\ 4 & 5 & 5 \\ 3 & 3 & 4 \end{matrix}

A:B:C → 4` \times `3 : 5` \times `3 : 5` \times `4

A:B:C → 12:15:20

If the ratio of a salary of A and B is 2:3, B and C is 4:5, C and D is 6:7. If the salary of A is 48000 then Find the salary of D.

\begin{matrix} A: & B: & C: & D \\ 2 & 3 & 3 & 3 \\ 4 & 4 & 5 & 5 \\ 6 & 6 & 6 & 7\end{matrix}

A:B:C:D à 48: 72: 90: 105

A:D = 48:105

`\frac { A }{ D }` = `\frac { 48 }{ 105 }`

`\frac { 48000 }{ D }` = `\frac { 48 }{ 105 }`

D’s salary = 105000

### TRICK 5: USAGE OF COMMON FACTOR ‘X’

Common factor “X” should be used only when there is no direct relation with ratio either directly or inversely#### Example:

**Two numbers are in the ratio 3:5. Sum of their squares is 30600. Find the numbers.**Ratio ⟶ 3: 5

Assume the actual number 3x and 5x

According to the question,

`(3x)^{ 2 }` + `(5x)^{ 2 }` = 30600

`34x^{ 2 }` = 30600

`x^{ 2 }` = 900

x = 30

Substitute the value of x in 3x and 5x to find numbers

Hence the numbers are 90 and 150

### TRICK 6: COIN PROBLEMS

Quantity Ratio ⟶ Q1 : Q2 : Q3Value Ratio⟶ V1 : V2 : V3

(Q1` \times `V1) + (Q2` \times `V2) + (Q3` \times `V3) = T

Common factor X = Total Amount/ T

Quantity of each coin = Q1X , Q2X, Q3X

#### Example:

**1. A bag contains 5 paisa, 10 paisa and 20 paisa coins in the ratio 2:4:5. Total amount in the bag is Rs. 4.50 How many coins are there of 20 paisa?****Solutions:**T = (5` \times `2) + (10` \times `4) + (20` \times `5)

T = 150 paisa = Rs. 1.50

X = `\frac { 4.50 }{ 1.50 }`4.50/ 1.50 = 3

Hence the quantity of 20 paisa coins = 5 ` \times ` 3 = 15 coins

**2. The bag contains 440 coins of 1 rupee, 50 paisa and 25 paisa and their value are in the ratio 6:7:9. Find the number of 50 paisa coins.****Solution:**Value Ratio ⟶ 6:7:9

Coins Ratio ⟶ 6` \times `1: 7` \times `2: 9` \times `4

3:7:18

Number of 50 paisa coins = `(\frac { 7 }{ 28 }) \times ` 440 = 110

## Examples of Ratio

We have explained some of the tricks of ratio in the first part of Ratio. Now we will discuss some more examples of the previous tricks of Ratio.### Example 1.

**If A:B is 2:5 and B:C is 7:3 then find A:B:C**

\begin{matrix} A: & B: & C \\ 2 & 5 & 5 \\ 7 & 7 & 3 \end{matrix}

A:B:C = 7`\times `2 : 7`\times `5 : 5`\times `3

A:B:C = 14:21:15

### Example 2.

**A wooden stick is broken into two parts one bigger and one smaller part. The ratio of the bigger part and the smaller part is proportional to the ratio of lengths of the full stick and bigger part. Find the ratio.**

Solution:

Let us consider the length of bigger part be 1 m and the smaller part be ‘x’ m.

So length of full stick = (1+x) m

Acc. to the ques.

`\frac { 1 }{ x } ` = `\frac { 1 + x }{ x } `

`x^{ 2 }` + x = 1

x = `\frac { (-1+\sqrt { 5 } ) }{ 2 }` (As the length will be positive)

### Example 3.

**Three persons A,B,C whose salary together amount to Rs. 96000. But the expenses of all three person is 75% , 85% and 80% of their salaries. If their savings is in the ratio of 8: 9:20. Find the salary of B**

**Solution:**

Let us suppose the salary of A be Rs. x, B be Rs. y and C be Rs. Z

Then the savings of them is

`\frac { (x\times 25)}{100}`, `\frac { (y\times 15)}{100}`, `\frac { (Z\times 20)}{100}`

`\frac { x }{ 4 }` , `\frac { 3y }{ 20 }`, `\frac { z }{ 5 }` = 8:9:20

x:y:z = 32:60:100 = 8:15:25

B’s salary will be `(\frac { 15 }{ 48 })\times ` 96000 = Rs. 30000

### Example 4.

**Seats in medical, commerce and art department in the college is in the ratio of 5:7:8. But due to the popularity of the college, management decided to increase the number of seats by 40%, 50% and 75% respectively. Find the new ratio of a number of seats available.**

**Solution:**

Initial ratio of seats = 5:7:8

There is increase of 40%, 50% and 75%

New ratio of seats:

5`\times ` 140% : 7`\times `150% : 8`\times ` 175%

7:`\frac { 21 }{ 2 } `:14

2:3:4

Hence the new ratio of seats is 2:3:4

### Example 5.

**The ratio of the first and second class fares between two railway stations in 4:1 and that of the number of passengers is 2:17. If on a day Rs. 2500 is collected as a fare. Find the amount collected from the second class passengers.**

**Solution:**

Given è Ratio of fares = 4:1

Ratio of number of passengers = 2:17

Ratio of amount collection = 4`\times `2 : 1`\times `17 = 8:17

Hence amount collected from second-class passengers is

`(\frac {17 }{ 25 } )\times ` 2500 = 1700

Required amount collection is Rs. 1700

### Example 6.

**Price of the diamond is directly proportional to the square of its weight. If the diamond is dropped and broken into three pieces of the ratio 1:2:3.If the price of original diamond is Rs. 1296 Find the loss after breakage of diamond**

**Solution:**

Let us consider the total weight be ‘x’

Acc. to ques. Weight is proportional to square of weight

`x^{ 2 }` = 1296

X = 36

After breakage ratio of weight = 1:2:3

Actual Weight = 6, 12, 18

Total value = `6^{ 2 }` + `12^{ 2 }` + `18^{ 2 }`

= 36+144+324 = 504

Loss after breakage = 1296 – 504 = 792

### Some Examples:

- A person covers a certain distance by train, bus and car in ratio 4:3:2. The ratio of the fare is 1:2:4 per km. The total expenditure as a fare is Rs.720. Find the total expenditure as fare on car
- A sum of money is distributed between A, B, C and D in the ratio 1:3:6:7. If the share of D is Rs.3744 more than A. Find the total amount of money of B&C together?
- A bag contains 1 rupee, 50 paisa and 25 paisa coins in the ratio 2:3:5. Their value is Rs.288. Find the value of 50 paisa coins.
- The salary of A,B, C are in the ratio of 2:3:5. If the increment of 10%, 15& and 20% are allowed respectively on new year. Find the ratio of new incremented salaries of A,B,C.
- In a business, A and C invested in the ratio 2:1 whereas the ratio between amount invested by A and B was 3:2. If Rs.1,57,300 was their profit. Find the amount invested by B.

## Proportion

The numbers or quantities are said to be in proportion when the two ratio between them are equal.For two ratio to be equal there is requirement of four variables.

If `\frac { a }{ b } = \frac {c }{ d } ` then a, b, c, d are said to be in proportion

This is expressed as ‘a’ is to ‘b’ is to ‘c’ is to ‘d’

And written as a:b :: c:d

( product of means = product of extremes)

### Mean or Third Proportion

When there are only three variables or quantities like a, b, c. Then the middle number is to be repeateda:b = b:c

Middle number b is called mean proportion and a and c are called extreme numbers.

`B^{ 2 }` = A`\times `C

### Example 1.

**Find the third proportion of 6 and 12**

`B^{ 2 }` = A`\times `C

`12^{ 2 }` = 6 `\times ` C

C = 24

### Some Examples:

- The fourth proportion to 75, 192 and 200 is equal to fourth proportion to 90, 384 and Q. Find the value of Q.
- What is the value of ‘x’ if it is 45% of the fourth proportion of 5, 8 and 25
- By how much the fourth proportion to 26, 143 and 68 will be greater than third proportion to 49 and 63?
- Find the mean proportion between (3+√2) and (12-√32)
- What is the least number must be subtracted from the numbers 14, 17, 34 and 42 so that the numbers may be in proportion?

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